How do you factor $27 x^{3} - 8 y^{3}$ $27x^3 -8y^3$ ?

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Answer 1 · 2016-09-02T22:27:46

$(3 x - 2 y) (9 y^{2} + 6 x y + 4 y^{2})$ $(3x-2y)(9y^2 + 6xy +4y^2)$

We should notice that every part of this expression is a cube.
We can factor it as the difference of cubes.

$27 x^{3} - 8 y^{3}$ $27x^3 -8y^3$

= $(3 x - 2 y) (9 y^{2} + 6 x y + 4 y^{2})$ $(3x-2y)(9y^2 + 6xy +4y^2)$

How do you factor 27x^3 -8y^327x3−8y327x^3 -8y^3?