How do you factor 2x^2+22x+56?

1 Answer
May 14, 2017

2(x+4)(x+7)

Explanation:

"take out a "color(blue)"common factor"" of 2"

rArr2(x^2+11x+28)

"to factor the quadratic 'split' the x term"

"that is " x^2+4x+7x+28

"factorising each 'pair' gives"

color(red)(x)(x+4)color(red)(+7)(x+4)

"take out the common factor " (x+4)

(x+4)(color(red)(x+7))

rArr2x^2+22x+56=2(x+4)(x+7)