How do you factor #2x^3-x^2-162x+81#?

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Answer 1 · 2017-02-10T13:49:33

#=(2x-1)(x-9)(x+9)#

You could factor the bynomial

#2x^3-x^2=x^2(2x-1)#

and the bynomial

#-162x+81=-81(2x-1)#

then the polynomial is:

#2x^3-x^2-162x+81=x^2(2x-1)-81(2x-1)#

It's possible factor again:

#=(2x-1)(x^2-81)=(2x-1)(x-9)(x+9)#