How do you factor # 2y^3 -128#?
1 Answer
May 29, 2016
Explanation:
Separate out the common scalar factor
#a^3-b^3=(a-b)(a^2+ab+b^2)#
with
#2y^3-128#
#=2(y^3-64)#
#=2(y^3-4^3)#
#=2(y-4)(y^2+y(4)+4^2)#
#=2(y-4)(y^2+4y+16)#
