How do you factor #3.375v^3+15.625r^6#? Algebra Polynomials and Factoring Factor Polynomials Using Special Products 1 Answer bp Apr 21, 2015 Prime factorise 3375 and 15625 3375=333555=#3^3*5^3# and 15625= 555555=# 5^3*5^3# #3.375v^3 +15.625r^6= (3^3*5^3* v^3 )/10^3 +( 5^3*5^3)/10^3 (r^2)^3# =# (5^3/10^3) [3^3 v^3 +5^3 (r^2)^3]# =#(5^3/10^3)[(3v)^3 +(5r^2)^3]# =#(5/10)^3 (3v+5r^2)(9v^2 -15vr^2 +25r^4)# =#1/8(3v+5r^2)(9v^2 -15vr^2 +25r^4)# Answer link Related questions How do you factor special products of polynomials? How do you identify special products when factoring? How do you factor #x^3 -8#? What are the factors of #x^3y^6 – 64#? How do you know if #x^2 + 10x + 25# is a perfect square? How do you write #16x^2 – 48x + 36# as a perfect square trinomial? What is the difference of two squares method of factoring? How do you factor #16x^2-36# using the difference of squares? How do you factor #2x^4y^2-32#? How do you factor #x^2 - 27#? See all questions in Factor Polynomials Using Special Products Impact of this question 1325 views around the world You can reuse this answer Creative Commons License