How do you factor #(-36u^-10 v^13)/(-51u^20 v^-11 )#?

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Answer 1 · 2017-06-17T12:38:52

#12/17 * v^24/u^30#

#36/51 * u^(-10-20) * v^(13+11)#

Answer 2 · 2017-06-19T19:46:14

This is only one term, so the only way we can factor is to write the product of the prime factors.

# (2^2 * 3v^24)/(17u^30)#

The fraction has to be simplified first:

#(-36u^-10v^13)/(-51u^20v^-11)#

#= (12v^13v^11)/(17u^20u^10)#

#=(12v^24)/(17u^30)#

#= (2^2 * 3v^24)/(17u^30)#