How do you factor #3xn^4-27x^3#? Algebra Polynomials and Factoring Factor Polynomials Using Special Products 1 Answer Harish Chandra Rajpoot Jul 2, 2018 #3x(n^2-3x)(n^2+3x)# Explanation: #3xn^4-27x^3# #=3x(n^4-9x^2)# #=3x((n^2)^2-(3x)^2)# #=3x(n^2-3x)(n^2+3x)# Answer link Related questions How do you factor special products of polynomials? How do you identify special products when factoring? How do you factor #x^3 -8#? What are the factors of #x^3y^6 – 64#? How do you know if #x^2 + 10x + 25# is a perfect square? How do you write #16x^2 – 48x + 36# as a perfect square trinomial? What is the difference of two squares method of factoring? How do you factor #16x^2-36# using the difference of squares? How do you factor #2x^4y^2-32#? How do you factor #x^2 - 27#? See all questions in Factor Polynomials Using Special Products Impact of this question 1513 views around the world You can reuse this answer Creative Commons License