How do you factor $3xy + 12x – 2y – 8$ ?

Question

2868 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-05-09T04:00:53

The answer is $(3x-2)(y+4)$ .

Factor $3xy+12x-2y-8$ .

There is no common factor, so use the factor by grouping method. Separate the terms into two groups.

$color(red)(3xy+12x)color(blue)(-(2y-8)$

Factor out $color(red)(3x)$ from the first group.

$color(red)(3x(y+4)color(blue)(-(2y-8)$

Factor out $color(blue)(-2$ from the second group.

$color(red)(3x(y+4)color(blue)((-2)(y+4)$

$color(purple)(y+4)$ is a common factor.

$color(red)(3x(y+4)color(blue)((-2)(y+4)$ =

$color(purple)((3x-2)(y+4)$

How do you factor 3xy + 12x – 2y – 8 3xy + 12x – 2y – 8 ?