How do you factor $44 + 15 h + h^{2}$ $44+15h+h^2$ ?

Question

1954 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-01-26T15:24:53

See the entire process below:

First, rewrite this equation in standard binomial form:

$h^{2} + 15 h + 44$ $h^2 + 15h + 44$

Now "play" with different multiples of $44$ $44$ (1x44, 2x22, 4x11) which also add up to $15$ $15$ giving:

$(h + 4) (h + 11)$ $(h + 4)(h + 11)$

How do you factor 44+15h+h^244+15h+h244+15h+h^2?