How do you factor $4 x^{2} - 36 y^{2}$ $4x^2-36y^2$ ?

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Answer 1 · 2016-01-08T15:04:49

(2x - 6y )(2x + 6y )

$a^{2} - b^{2}$ $a^2 - b^2$

is a difference of two squares since the values on either side of the difference (- ) are perfect squares. the factor of

$a^{2} - b^{2} = (a - b) (a + b)$ $a^2 - b^2 = (a - b)(a + b )$

in the question given then a = 2x and b = 6y

$\Rightarrow 4 x^{2} - 36 y^{2} = (2 x - 6 y) (2 x + 6 y)$ $rArr 4x^2- 36y^2 = (2x - 6y )(2x + 6y )$

How do you factor 4x^2-36y^2 4x2−36y24x^2-36y^2 ?