Question

How do you factor #4y=x^2 + 8x + 15 #?

Answer 1

`y=((x+5)(x+3))/4`

Explanation:

`4y=x^2+8x+15`
or
`4y=x^2+5x+3x+15`
or
`4y=x(x+5)+3(x+5)`
or
`4y=(x+5)(x+3)`
or
`y=((x+5)(x+3))/4`