How do you factor #6k^2h^4-54k^4#? Algebra Polynomials and Factoring Factor Polynomials Using Special Products 1 Answer Robert W. · EZ as pi Jun 30, 2017 #6k^2(h^2-3k) (h^2+3k)# Explanation: Factor the #6k^2# out first: #6k^2(h^4 -9k^2)# You're left with the difference of two squares. Answer link Related questions How do you factor special products of polynomials? How do you identify special products when factoring? How do you factor #x^3 -8#? What are the factors of #x^3y^6 – 64#? How do you know if #x^2 + 10x + 25# is a perfect square? How do you write #16x^2 – 48x + 36# as a perfect square trinomial? What is the difference of two squares method of factoring? How do you factor #16x^2-36# using the difference of squares? How do you factor #2x^4y^2-32#? How do you factor #x^2 - 27#? See all questions in Factor Polynomials Using Special Products Impact of this question 1820 views around the world You can reuse this answer Creative Commons License