How do you factor $6t^4 + t^2 - 12$ ?

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Answer 1 · 2016-04-22T10:51:07

$(sqrt3*t+2)(sqrt3*t-2)(2t^2+3)$

$6t^4+t^2-12 =6t^4+9t^2-8t^2-12=3t^2(2t^2+3)-4(2t^2+3) =(3t^2-4)(2t^2+3)=(sqrt3*t+2)(sqrt3*t-2)(2t^2+3)$ [Ans]

How do you factor 6t^4 + t^2 - 126t^4 + t^2 - 12?