How do you factor 8x^2-10xy+3y^28x2−10xy+3y2?

1 Answer
Nghi N.
Oct 16, 2015

Factor: f(x, y) = 8x^2 - 10xy + 3y^2f(x,y)=8x2−10xy+3y2

Ans: (2x - y)(4x - 3y)

Explanation:

Find 2 numbers p and q, knowing (pq) = 24 and (p + q) = -10. They are -4 and -6. Replace the term -10xy by the 2 terms -4xy and - 6xy.
f(x, y) = 8x^2 - 4xy - 6xy + 3y^2.f(x,y)=8x2−4xy−6xy+3y2.
f(x, y) = 4x(2x - y) - 3y(2x - y)
f(x. y) = (2x - y)(4x - 3y)
Check by developing:
8x^2 - 6xy - 4xy + 3y^2 = 8x^2 - 10xy + 3y^2.8x2−6xy−4xy+3y2=8x2−10xy+3y2. OK

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