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How do you factor #8x^4-128#?

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Konstantinos Michailidis

Dec 26, 2015

It is

#8x^4-128=8*(x^4-16)=8*(x^4-2^4)=8*(x^2-4)*(x^2+4)=8*(x-2)*(x+2)*(x^2+4)#

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