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How do you factor $a^{2} + 10 a b - 39 b^{2}$ $a^2+10ab-39b^2$ ?

1 Answer

Jul 5, 2017

Paly with factors of $39$ $39$ (1, 3, 13, 39) gives:

$(a - 3 b) (a + 13 b)$ $(a - 3b)(a + 13b )$

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