How do you factor and solve $b^2-\frac{5}{3b}=0$ ?

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Answer 1 · 2014-11-01T12:45:39

$b^2-5/{3b}=0$

by multiplying by $b$ ,

$=> b^3-5/3=0$

by $5/3=(root3{5/3})^3$ ,

$=> b^3-(root3{5/3})^3=0$

by $(a^3-b^3)=(a-b)(a^2+ab+b^2)$ ,

$=> (b-root3{5/3})[b^2+root3{5/3}b+(root3{5/3})^2]=0$

since $b^2+root3{5/3}b+(root3{5/3})^2 ne 0$ ,

$=> b-root3{5/3}=0 => b=root3{5/3}$

I hope that this was helpful

How do you factor and solve b^2-\frac{5}{3b}=0b^2-\frac{5}{3b}=0?