How do you factor $b^{2} + 16 b + 64$ $b^2+16b+64$ ?

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Answer 1 · 2015-05-15T23:34:30

That $64 = 8 \cdot 8$ $64 = 8*8$ and $16 = 8 + 8$ $16 = 8+8$ is a bit of a give away:

${(b + 8)}^{2} = (b + 8) (b + 8)$ $(b+8)^2 = (b+8)(b+8)$

$= b \cdot b + 8 b + 8 b + 8 \cdot 8 = b^{2} + 16 b + 64$ $= b*b + 8b + 8b + 8*8 = b^2 + 16b + 64$

How do you factor b2+16b+64b^2+16b+64?