How do you factor #b^3 - 8#? Algebra Polynomials and Factoring Factor Polynomials Using Special Products 1 Answer Nityananda · Nam D. Mar 7, 2018 #(b-2)(b^2+2b+4)# Explanation: #b^3-8 # #rArr (b)^3-(2)^3# #rArr (b-2)^3+3*b*2(b-2)# #rArr (b-2)[(b-2)^2+6b]# #rArr (b-2)[b^2-4b+4+6b]# #rArr (b-2)(b^2+2b+4)# Answer link Related questions How do you factor special products of polynomials? How do you identify special products when factoring? How do you factor #x^3 -8#? What are the factors of #x^3y^6 – 64#? How do you know if #x^2 + 10x + 25# is a perfect square? How do you write #16x^2 – 48x + 36# as a perfect square trinomial? What is the difference of two squares method of factoring? How do you factor #16x^2-36# using the difference of squares? How do you factor #2x^4y^2-32#? How do you factor #x^2 - 27#? See all questions in Factor Polynomials Using Special Products Impact of this question 2423 views around the world You can reuse this answer Creative Commons License