How do you factor $d^{2} + 3 d - 4$ $d^2+3d-4$ ?

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Answer 1 · 2015-05-26T12:04:48

Note that $(4) \times (- 1) = - 4$ $(4)xx(-1) = -4$
and
$(4) + (- 1) = 3$ $(4) + (-1) = 3$

Therefore $d^{2} + 3 d - 4$ $d^2+3d-4$ can be factored as
$(d + 4) (d - 1)$ $(d+4)(d-1)$

How do you factor d2+3d−4d^2+3d-4?