How do you factor #gx^2 - 3hx^2 - 6fy^2 - gy^2 + 6fx^2 + 3hy^2#? Algebra Polynomials and Factoring Factor Polynomials Using Special Products 1 Answer Ratnaker Mehta Aug 4, 2016 #(x+y)(x-y)(g-3h+6f)#. Explanation: Rearranging the terms, the Expression #=gx^2-gy^2-3hx^2+3hy^2+6fx^2-6fy^2# #=g(x^2-y^2)-3h(x^2-y^2)+6f(x^2-y^2)# #=(x^2-y^2)(g-3h+6f)# #=(x+y)(x-y)(g-3h+6f)#. Answer link Related questions How do you factor special products of polynomials? How do you identify special products when factoring? How do you factor #x^3 -8#? What are the factors of #x^3y^6 – 64#? How do you know if #x^2 + 10x + 25# is a perfect square? How do you write #16x^2 – 48x + 36# as a perfect square trinomial? What is the difference of two squares method of factoring? How do you factor #16x^2-36# using the difference of squares? How do you factor #2x^4y^2-32#? How do you factor #x^2 - 27#? See all questions in Factor Polynomials Using Special Products Impact of this question 3829 views around the world You can reuse this answer Creative Commons License