How do you factor $m^{2} + m - 20$ $m^2+m-20$ ?

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Answer 1 · 2015-06-19T13:22:26

$m^{2} + m - 20 = (m + 5) (m - 4)$ $m^2+m-20 = (m+5)(m-4)$

We are looking for factors of $(- 20)$ $(-20)$ [one positive and one negative] whose sum is $1$ $1$ .

Note: I modified the question replacing an $x$ $x$ with a second $m$ $m$ .

How do you factor m2+m−20m^2+m-20?