How do you factor $n^{2} - 3 n + 9$ $n^2 - 3n + 9$ ?

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Answer 1 · 2016-05-27T14:34:15

i believe it's factored as far as it will go - if i am wrong, please correct me :)

you want to find two numbers that add to -3 and multiply to 9. since only
1, 9
-1, -9
3, 3
-3, -3

none of these combinations add to be -3

How do you factor n^2 - 3n + 9n2−3n+9 n^2 - 3n + 9?