Question

How do you factor `t^2 + 16t + 60`?

Answer 1

`(t + 10)(t +6)`

Explanation:

This is simple. No need to worry about.

If we have `ax^2 + bx + c` to factor, we should break `b` to `p + q` such that `pq = ac`.

We have,

`color(white)(xxx)t^2 +16t + 60`

`= t^2 + (10 + 6)t + 60` [As `6 xx 10 = 60`]

`= t^2 + 10t + 6t + 60` [Distributive Property]

`= t(t + 10) + 6(t + 10)` [Grouping like terms]

`= (t + 10)(t +6)` [Grouping Again]

And Done. Hope this helps.