How do you factor the expression #16x^2 - 49#? Algebra Polynomials and Factoring Factorization of Quadratic Expressions 1 Answer Megan T. · Stefan V. Apr 6, 2018 #(4x-7)(4x+7)# Explanation: #16x^2 + 28x - 28x - 49# #+28x - 28x = 0# as they cancel each other out, leaving you with #16x^2 - 49# Answer link Related questions How do you factor trinomials? What is factorization of quadratic expressions? How do you factor quadratic equations with a coefficient? What are some examples of factoring quadratic expressions? How do you check that you factored a quadratic correctly? How do you factor #x^2+16x+48#? How do you factor #x^2-9x+20#? Question #3fdac How do you factor #8+z^6#? There is no GCF to be factor out, so is there another method to complete this? How do you factor #2t^2+7t+3#? See all questions in Factorization of Quadratic Expressions Impact of this question 7129 views around the world You can reuse this answer Creative Commons License