Question

How do you factor the following differences of two cubes `54x^3-16y^6`?

Answer 1

In this way:

`54x^3-16y^6=2(27x^3-8y^6)=`

`=2(3x-2y^2)(9x^2+6xy^2+4y^4)`.

The rule is:

`a^3-b^3=(a-b)(a^2+ab+b^2)`.