How do you factor the sum or difference of two cubes #64m^3n^3+216m^3p^3#?

1 Answer
bp
Apr 15, 2015

8#m^3# (2n+3p) (4#n^2# -6np + 9#p^2#)

Write the numbers as perfect cubes by first taking out 8#m^3# as a common factor like this 8#m^3#{ #(2n)^3# + #(3p)^3#}. Using the algebraic identity for factorising the sum of two cubes, the factorisation would be 8#m^3# (2n+3p) (4#n^2# -6np + 9#p^2#)

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