How do you factor the trinomial #4x^2 + 12x + 9#? Algebra Polynomials and Factoring Factorization of Quadratic Expressions 1 Answer Shwetank Mauria Apr 24, 2016 #4x^2+12x+9=(2x+3)(2x+3)# Explanation: If we have a trinomial #ax^2+bx+c#, we split middle term #b# so the product of its parts is #axxc#. Here in #4x^2+12x+9#, product is #36# and we can split #12x# in to #6x+6x# which gives us #4x^2+6x+6x+9# or #2x(2x+3)+3(2x+3)# or #(2x+3)(2x+3)#. Answer link Related questions How do you factor trinomials? What is factorization of quadratic expressions? How do you factor quadratic equations with a coefficient? What are some examples of factoring quadratic expressions? How do you check that you factored a quadratic correctly? How do you factor #x^2+16x+48#? How do you factor #x^2-9x+20#? Question #3fdac How do you factor #8+z^6#? There is no GCF to be factor out, so is there another method to complete this? How do you factor #2t^2+7t+3#? See all questions in Factorization of Quadratic Expressions Impact of this question 19884 views around the world You can reuse this answer Creative Commons License