Question

How do you factor the trinomial `6d^2+21d= 10d+35`?

Answer 1

Rearrange all the factors to be on one side of the expression and then factorize as normal

Explanation:

`6d^2 +21d - 10d -35 = 0`
`6d^2 +11d -35 = 0`
35 is `7*5` and 6 is `3*2`
By studying the numbers 11 can be obtained from 21 (`7*3`) minus 10 (`5*2`)
`(3d - 5)(2d + 7) = 0`
`d = 5/3` or `d = -7/2`