How do you factor #(x^2 +1)^(1/2) + 2(x^2 +1)^(-1/2)#? Algebra Polynomials and Factoring Factorization of Quadratic Expressions 1 Answer Jim H Sep 26, 2015 See explanation. Explanation: Remove a factor #(x^2+1)^(-1/2)# (the lesser power) #(x^2+1)^(-1/2)[(x^2+1)+2]# # = (x^2+1)^(-1/2)(x^2+3)# Answer link Related questions How do you factor trinomials? What is factorization of quadratic expressions? How do you factor quadratic equations with a coefficient? What are some examples of factoring quadratic expressions? How do you check that you factored a quadratic correctly? How do you factor #x^2+16x+48#? How do you factor #x^2-9x+20#? Question #3fdac How do you factor #8+z^6#? There is no GCF to be factor out, so is there another method to complete this? How do you factor #2t^2+7t+3#? See all questions in Factorization of Quadratic Expressions Impact of this question 1829 views around the world You can reuse this answer Creative Commons License