How do you factor $x^{2} + 17 x + 42 = 0$ $x^2 +17x +42= 0$ ?

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Answer 1 · 2015-06-03T11:27:12

Notice that $3 \times 14 = 42$ $3xx14=42$ and $3 + 14 = 17$ $3+14=17$

So $(x + 3) (x + 14) = x^{2} + (3 + 14) x + (3 \times 14) = x^{2} + 17 x + 42$ $(x+3)(x+14) = x^2+(3+14)x+(3xx14) = x^2+17x+42$

How do you factor x2+17x+42=0x^2 +17x +42= 0?