How do you factor #x^2 +17x +42= 0#? Algebra Polynomials and Factoring Factorization of Quadratic Expressions 1 Answer George C. Jun 3, 2015 Notice that #3xx14=42# and #3+14=17# So #(x+3)(x+14) = x^2+(3+14)x+(3xx14) = x^2+17x+42# Answer link Related questions How do you factor trinomials? What is factorization of quadratic expressions? How do you factor quadratic equations with a coefficient? What are some examples of factoring quadratic expressions? How do you check that you factored a quadratic correctly? How do you factor #x^2+16x+48#? How do you factor #x^2-9x+20#? Question #3fdac How do you factor #8+z^6#? There is no GCF to be factor out, so is there another method to complete this? How do you factor #2t^2+7t+3#? See all questions in Factorization of Quadratic Expressions Impact of this question 1433 views around the world You can reuse this answer Creative Commons License