How do you factor $x^2-3x-10$ ?

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Answer 1 · 2016-11-02T08:37:18

$x^2-3x-10 = (x-5)(x+2)$

Given:

$x^2-3x-10$

Find a pair of factors of $10$ which differ by $3$ .

The pair $5, 2$ works in that $5*2=10$ and $5-2=3$

Hence we find:

$x^2-3x-10 = (x-5)(x+2)$

How do you factor x^2-3x-10x^2-3x-10?