How do you factor $x^{2} - 4 x + 3$ $x^2-4x+3$ ?

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Answer 1 · 2018-06-08T20:27:13

$(x - 3) (x - 1)$ $(x-3)(x-1)$

Using the quadratic formula
$x_{1, 2} = 2 \pm \sqrt{4 - 3}$ $x_{1,2}=2pmsqrt(4-3)$
so
$x_{1} = 3$ $x_1=3$
$x_{2} = 1$ $x_2=1$

How do you factor x2−4x+3x^2-4x+3?