How do you factor $x^{2} - 4 x + 4 = 0$ $x^2 - 4x + 4 =0$ ?

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Answer 1 · 2016-07-27T11:42:20

$(x - 2) (x - 2) = 0$ $(x-2)(x-2) = 0$
$x = 2$ $x = 2$

To factor the expression you need to find factors of 4 which add up to 4.

The signs will be the same (because of +4), they are both minus (because of -4x).

$2 \times 2 = 4 and 2 + 2 = 4$ $2 xx2 = 4 and 2 + 2 = 4$

$(x - 2) (x - 2) = 0$ $(x-2)(x-2) = 0$

Now that we have the factors, we can solve:
If $x - 2 = 0, then x = 2$ $x - 2 =0", then "x =2$

How do you factor x2−4x+4=0x^2 - 4x + 4 =0?