How do you factor #x^2 - 4x = 5#? Algebra Polynomials and Factoring Factorization of Quadratic Expressions 1 Answer Barney V. · EZ as pi Dec 23, 2016 #(x-5)(x+1)=0# Explanation: #x^2-4x=5# #x^2-4x-5=0# #(x-5)(x+1)=0# #(x-5)xx(x+1)=0" "#multiply out to check #x^2+x-5x -5=0# #x^2-4x-5=0# #x^2-4x=5# Answer link Related questions How do you factor trinomials? What is factorization of quadratic expressions? How do you factor quadratic equations with a coefficient? What are some examples of factoring quadratic expressions? How do you check that you factored a quadratic correctly? How do you factor #x^2+16x+48#? How do you factor #x^2-9x+20#? Question #3fdac How do you factor #8+z^6#? There is no GCF to be factor out, so is there another method to complete this? How do you factor #2t^2+7t+3#? See all questions in Factorization of Quadratic Expressions Impact of this question 3820 views around the world You can reuse this answer Creative Commons License
