How do you factor $x^{2} - 4 y^{2}$ $x^2-4y^2$ ?

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Answer 1 · 2018-03-05T00:12:03

The factored expression is $(x - 2 y) (x + 2 y)$ $(x-2y)(x+2y)$ .

You can write the expression as a difference of squares, then use a special factoring form:

$a^{2} - b^{2} = (a - b) (a + b)$ $color(red)a^2-color(blue)b^2=(color(red)a-color(blue)b)(color(red)a+color(blue)b)$

Here's the actual problem:

$= x^{2} - 4 y^{2}$ $color(white)=x^2-4y^2$

$= x^{2} - 2^{2} y^{2}$ $=x^2-2^2y^2$

$= {(x)}^{2} - {(2 y)}^{2}$ $=(x)^2-(2y)^2$

$= (x - 2 y) (x + 2 y)$ $=(x-2y)(x+2y)$

That's as factored as it gets.

How do you factor x^2-4y^2x2−4y2x^2-4y^2?