How do you factor x^3 - 8y^3x3−8y3?
3 Answers
Explanation:
Explanation:
x^3-8y^3larrcolor(blue)"is a difference of cubes"x3−8y3←is a difference of cubes
•color(white)(x)a^3-b^3=(a-b)(a^2+ab+b^2)∙xa3−b3=(a−b)(a2+ab+b2)
"here "a=x" and "b=2yto(2y)^3=8y^3here a=x and b=2y→(2y)3=8y3
rArrx^3-8y^3=(x-2y)(x^2+2xy+4y^2)⇒x3−8y3=(x−2y)(x2+2xy+4y2)
Explanation:
Factor:
Apply the difference of cubes:
where:
Plug in the known values.
Apply multiplicative distributive property:
Simplify.