Question

How do you factor `y^3+27`?

Answer 1

`(y+3)(y^2 -3y + 9)`

Explanation:

This is the sum of two cubes. `(y^3 +27)`

Once recognised it is easily factored because the factors follow the same pattern

`y^3 + 27`
=`(y+3)(y^2 -3y + 9)`