How do you find 2 points that lie on the graph of this equation other than the x and y intercepts $3 y + 2 x = 6$ $3y + 2x = 6$ ?

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Answer 1 · 2016-08-29T11:01:50

$(9, - 4) and (- 9, 8)$ $(9,-4) and (-9,8)$

Choose any x-value, substitute and work out the y-value,
Or, choose a y-value, substitute and work out the x-value.

Re-arrange the equation to make this easier.

$y = - \frac{2}{3} x + 2$ $y = -2/3x +2$ ( choose x as a multiple of 3)

Or

$x = - \frac{3}{y} 2 + 3$ $x =-3/y2 +3$ (choose even values of y)

For example:
$x = 9, y = - \frac{2}{3} \times (9) + 2 = - 4 \to (9, - 4)$ $x = 9, " "y = -2/3xx (9) +2 = -4 rarr (9,-4)$

$y = 8, x = - \frac{3}{2} \times (8) + 3 = - 9 \to (- 9, 8)$ $y = 8, " " x = -3/2 xx(8) +3 = -9 rarr (-9,8)$

You can choose any number of values for x and/or y to find as many points as you need.

How do you find 2 points that lie on the graph of this equation other than the x and y intercepts 3y+2x=63y + 2x = 6?