How do you find a slope of (3/4,-2) and (1/4,-3)?

Question

How do you find a slope of (3/4,-2) and (1/4,-3)?

1 Answer

Impact of this question

1437 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-05-17T13:48:46

The slope is $2$ $2$ .

Explanation:

The slope given two points on a Cartesian Plane, $(x_{1}, y_{1})$ $(x_1,y_1)$ and $(x_{2}, y_{2})$ $(x_2,y_2)$ is $\frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ $(y_2-y_1)/(x_2-x_1)$

Hence, slope given two points $(\frac{3}{4}, - 2)$ $(3/4,-2)$ and $(\frac{1}{4}, - 3)$ $(1/4,-3)$ should be

$\frac{- 3 - (- 2)}{\frac{1}{4} - \frac{3}{4}} = \frac{- 3 + 2}{- \frac{2}{4}} = \frac{- 1}{- \frac{2}{4}} = \frac{1 \times 4}{2} = 2$ $(-3-(-2))/(1/4-3/4)=(-3+2)/(-2/4)=(-1)/(-2/4)=(1xx4)/2=2$

Hence, the slope is $2$ $2$ .

Science

Math

Humanities

... and beyond

How do you find a slope of (3/4,-2) and (1/4,-3)?

1 Answer

Explanation:

Related questions

Impact of this question