How do you find a slope of (8,2) and (10,-2)?

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Answer 1 · 2018-04-17T12:53:52

$-2$

Slope of a line is given by:

$m=(y_2-y_1)/(x_2-x_1)$

$(x_1,y_1)$ are the coordinates of the first point

$(x_2,y_2)$ are the coordinates of the second point

We got: $(x_1,y_1)=(8,2),(x_2,y_2)=(10,-2)$ .

$:.x_1=8,y_1=2,x_2=10,y_2=-2$

And so,

$m=(-2-2)/(10-8)$

$=(-4)/2$

$=-2$