Question

How do you find a standard form equation for the line with (-2,3) with an x-intercept of 0?

Answer 1

`3x+2y=0`

Explanation:

The x-intercept is the value of `x` when `y=0`.
So if the x-intercept is `0`, the line must pass through the point `(0,0)`

Since `(-2,3)` and `(0,0)`are points on this line, the slope of this line is `m=(Deltay)/(Deltax)=-3/2`

Using the slope-point form and the point `(0,0)`
we have `y-0=-3/2(x-0)`
or
`color(white)("XX")2y=-3x`

which in standard form (`Ax+By=C`) can be written as
`color(white)("XX")3x+2y=0`