How do you find a) u+v, b) u-v, c) 2u-3v given $u = 2 i, v = j$ $u=2i, v=j$ ?

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Answer 1 · 2017-08-03T06:33:26

See the explanation below

The $2$ $2$ vectors are

$\to u = 2 \to i$ $vecu=2veci$

$\to v = \to j$ $vecv=vecj$

$(a)$ $(a)$ addition of the $2$ $2$ vectors

$\to u + \to v = 2 \to i + \to j$ $vecu+vecv=2veci+vecj$

$(b)$ $(b)$ substraction of the $2$ $2$ vectors

$\to u - \to v = 2 \to i - \to j$ $vecu-vecv=2veci-vecj$

$(c)$ $(c)$ multiplication by a scalar and substraction of the $2$ $2$ vectors

$2 \to u - 3 \to v = 2 \times 2 \to i - 3 \times \to j = 4 \to i - 3 \to j$ $2vecu-3vecv=2xx2veci-3xxvecj=4veci-3vecj$

How do you find a) u+v, b) u-v, c) 2u-3v given u=2i,v=ju=2i, v=j?