How do you find #abs( -1 + 2i )#?
1 Answer
Mar 19, 2016
Explanation:
Given a complex number z = x + iy then the magnitude is
|z| = |x +iy|
#= sqrt( x^2 + y^2) # here x = -1 and y = 2
hence |-1 + 2i|
# = sqrt((-1)^2 + 2^2) = sqrt5 #