How do you find $abs( 14i )$ ?

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Answer 1 · 2016-04-04T12:23:18

$|14i| = 14$

Given a complex number $a+bi$ , the modulus $|a+bi|$ of the complex number is given by

$|a+bi| = sqrt(a^2+b^2)$

In this case, we have

$|14i| = |0+14i| = sqrt(0^2+14^2) = 14$

Note that in general, for any $binRR$ , we have $|bi| = sqrt(b^2) = |b|$

Answer 2 · 2016-04-04T12:25:39

14

$|ab|=|a||b|$ .
i is unit vector in the direction of the axis of imaginaries. $|i|=1$ .

How do you find abs( 14i )abs( 14i )?