How do you find #abs(2 - 4i)#?
1 Answer
May 29, 2016
Explanation:
Given a complex number z = x + iy , then it's magnitude is found as follows
#color(red)(|bar(ul(color(white)(a/a)color(black)(r=|z|=|x+iy|=sqrt(x^2+y^2))color(white)(a/a)|)))# here x = 2 and y = -4
#rArr|2-4i|=sqrt(2^2+(-4)^2)=sqrt20=2sqrt5#