How do you find #abs(2+4i )#?
1 Answer
Apr 8, 2016
Explanation:
Given a complex number z = x + yi then the modulus of z is.
#|z| = | x+yi| = sqrt( x^2 + y^2) #
#rArr |2+4i| = sqrt(2^2+4^2) = sqrt20 = 2sqrt5 #
