How do you find #abs(2 +5i)#? Precalculus Complex Numbers in Trigonometric Form Complex Number Plane 1 Answer Ratnaker Mehta Jul 19, 2016 #|2+5i|=sqrt29~=5.385#. Explanation: #|x+iy|=sqrt(x^2+y^2)#. #:. |2+5i|=sqrt{2^2+5^2}=sqrt(4+25)=sqrt29~=5.385#. Answer link Related questions What is the complex number plane? Which vectors define the complex number plane? What is the modulus of a complex number? How do I graph the complex number #3+4i# in the complex plane? How do I graph the complex number #2-3i# in the complex plane? How do I graph the complex number #-4+2i# in the complex plane? How do I graph the number 3 in the complex number plane? How do I graph the number #4i# in the complex number plane? How do I use graphing in the complex plane to add #2+4i# and #5+3i#? How do I use graphing in the complex plane to subtract #3+4i# from #-2+2i#? See all questions in Complex Number Plane Impact of this question 1183 views around the world You can reuse this answer Creative Commons License