Question

How do you find `abs( 2 + 8i )`?

Answer 1

`abs(2+8i) = 2sqrt(17)`

Explanation:

In general `abs(a+bi) = sqrt(a^2+b^2)`

So
`color(white)("XXX")abs(2+8i) = sqrt(2^2+8^2) = sqrt(68)=2sqrt(17)`