Question

How do you find `abs( 2 − i )`?

Answer 1

`|2-i|=sqrt5`

Explanation:

The absolute value of complex number `a+bi` is written as `|a+bi|` and is equivalent to `sqrt(a^2+b^2)`.

Hence `|2-i|`

= `sqrt(2^2+(-1)^2)`

= `sqrt(4+1)`

= `sqrt5`